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sec-2-1-sec-2-2-sec-2-3-sec-2-89-




Question Number 165403 by naka3546 last updated on 01/Feb/22
sec^2 1° + sec^2  2° + sec^2  3° + …+ sec^2  89° = ?
$$\mathrm{sec}^{\mathrm{2}} \mathrm{1}°\:+\:\mathrm{sec}^{\mathrm{2}} \:\mathrm{2}°\:+\:\mathrm{sec}^{\mathrm{2}} \:\mathrm{3}°\:+\:\ldots+\:\mathrm{sec}^{\mathrm{2}} \:\mathrm{89}°\:=\:? \\ $$

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