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sec-2-1-sec-2-2-sec-2-3-sec-2-89-




Question Number 166685 by cortano1 last updated on 25/Feb/22
   sec^2 1°+sec^2 2°+sec^2 3°+...+sec^2 89°=?
$$\:\:\:\mathrm{sec}\:^{\mathrm{2}} \mathrm{1}°+\mathrm{sec}\:^{\mathrm{2}} \mathrm{2}°+\mathrm{sec}\:^{\mathrm{2}} \mathrm{3}°+…+\mathrm{sec}\:^{\mathrm{2}} \mathrm{89}°=? \\ $$

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