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sec-tan-d-sec-tan-




Question Number 64733 by mmkkmm000m last updated on 20/Jul/19
∫(secθtanθ)dθ/secθ+^− tanθ
$$\int\left({sec}\theta{tan}\theta\right){d}\theta/{sec}\theta\overset{−} {+}{tan}\theta \\ $$

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