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sec-x-1-sec-x-1-sec-x-1-1-1-sec-x-1-sec-x-1-2-sec-x-1-sec-x-1-sec-x-1-2-sec-x-1-1-2-sec-x-1-1-2-sec-x-1-1-d-dx-1-2-sec-x-1-1-2-1-sec-x-1-2-

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Question Number 19658 by icyfalcon999 last updated on 14/Aug/17
=((sec x−1)/(sec x+1)) =((sec x+(1−1)−1)/(sec x+1)) =(((sec x+1)−2)/(sec x+1)) =((sec x+1)/(sec x+1))−(2/(sec x+1)) =1−(2/(sec x+1)) =1−2(sec x+1)^(−1) (d/dx)(1−2(sec x+1)^(−1) ) =−2(−1(sec x+1)^(−2) )(sec x tan x) =((2 sec x tan x)/((sec x+1)^2 ))
=secx−1secx+1=secx+(1−1)−1secx+1=(secx+1)−2secx+1=secx+1secx+1−2secx+1=1−2secx+1=1−2(secx+1)−1ddx(1−2(secx+1)−1)=−2(−1(secx+1)−2)(secxtanx)=2secxtanx(secx+1)2

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