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sec-xcos-5x-1-0-find-number-of-solution-




Question Number 17100 by virus last updated on 30/Jun/17
sec xcos 5x+1=0  find number of solution
secxcos5x+1=0findnumberofsolution
Answered by Tinkutara last updated on 01/Jul/17
cos 5x + cos x = 0  2 cos 3x cos 2x = 0  Either cos 3x = 0 or cos 2x = 0  ⇒ x = (2n + 1)(π/6) or (2k + 1)(π/4)  There should be infinite number of  solutions.
cos5x+cosx=02cos3xcos2x=0Eithercos3x=0orcos2x=0x=(2n+1)π6or(2k+1)π4Thereshouldbeinfinitenumberofsolutions.

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