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show-by-recurrence-that-integer-p-0-3-p-p-3-




Question Number 126537 by mathocean1 last updated on 21/Dec/20
show by recurrence that ∀  integer p≥0, 3^p ≥p^3
$${show}\:{by}\:{recurrence}\:{that}\:\forall \\ $$$${integer}\:{p}\geqslant\mathrm{0},\:\mathrm{3}^{{p}} \geqslant{p}^{\mathrm{3}} \\ $$

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