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Question Number 110112 by mathdave last updated on 27/Aug/20
show that   ∫_0 ^∞ xsin(x^3 )dx=(1/3)•(π/(Γ((1/3))))
showthat0xsin(x3)dx=13πΓ(13)
Answered by mnjuly1970 last updated on 27/Aug/20
x^3 =t⇒{_(dx=(1/3)t^((−2)/3) dt) ^(x=t^(1/3) )   we know::   ∫_0 ^( ∞) ((sin(x))/x^p )dx =^(0<p≤1) (π/(2Γ(p)sin(((pπ)/2))))         Ω=∫_0 ^( ∞) xsin(x^3 )dx=(1/3)∫_0 ^( ∞) ((sin(t))/t^(1/3) )dt   Ω=(1/3)∗ (π/(2Γ((1/3))sin((π/6)))) =(π/(3Γ((1/3)))) ♣  M.N.July 1970
x3=t{dx=13t23dtx=t13weknow::0sin(x)xpdx=0<p1π2Γ(p)sin(pπ2)Ω=0xsin(x3)dx=130sin(t)t13dtΩ=13π2Γ(13)sin(π6)=π3Γ(13)M.N.July1970
Commented by mathdave last updated on 27/Aug/20
u did well man
udidwellman
Commented by mnjuly1970 last updated on 27/Aug/20
grateful...sir....
gratefulsir.

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