show-that-0-xsin-x-3-dx-1-3-pi-1-3- Tinku Tara June 4, 2023 None 0 Comments FacebookTweetPin Question Number 110112 by mathdave last updated on 27/Aug/20 showthat∫0∞xsin(x3)dx=13∙πΓ(13) Answered by mnjuly1970 last updated on 27/Aug/20 x3=t⇒{dx=13t−23dtx=t13weknow::∫0∞sin(x)xpdx=0<p⩽1π2Γ(p)sin(pπ2)Ω=∫0∞xsin(x3)dx=13∫0∞sin(t)t13dtΩ=13∗π2Γ(13)sin(π6)=π3Γ(13)♣M.N.July1970 Commented by mathdave last updated on 27/Aug/20 udidwellman Commented by mnjuly1970 last updated on 27/Aug/20 grateful…sir…. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-175644Next Next post: Question-175655 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.