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Question Number 167928 by Mastermind last updated on 29/Mar/22

S h o w t h a t ∣ 1 - i ∣^{x} = 2^{x} h a s n o n o n z e r o i n t e g r a l s o l u t i o n

Answered by MJS_new last updated on 30/Mar/22

∣ 1 - i ∣= \sqrt{2}; ∣ 1 - i ∣^{x} = {(\sqrt{2})}^{x} = 2^{\frac{x}{2}}

2^{\frac{x}{2}} = 2^{x}

(2^{\frac{x}{2}}) = {(2^{\frac{x}{2}})}^{2}

\Rightarrow 2^{\frac{x}{2}} = 0 \lor 2^{\frac{x}{2}} = 1 \Rightarrow x = - \infty \lor x = 0

Commented by Mastermind last updated on 31/Mar/22

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