Question Number 165461 by mathocean1 last updated on 01/Feb/22
$${show}\:{that}\:{argth}\left({x}\right)=\frac{\mathrm{1}}{\mathrm{2}}{ln}\left(\frac{\mathrm{1}+{x}}{\mathrm{1}−{x}}\right) \\ $$$$\left.{for}\:{x}\:\in\:\right]−\mathrm{1};\mathrm{1}\left[\right. \\ $$