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Question Number 119891 by sdfg last updated on 27/Oct/20
show that (d/dx) Γ(x)=∫_0 ^∞ t^(x−1) e^(−t) lnt dt
$${show}\:{that}\: \\ $$$$\frac{{d}}{{dx}}\:\Gamma\left({x}\right)=\int_{\mathrm{0}} ^{\infty} {t}^{{x}−\mathrm{1}} {e}^{−{t}} {lnt}\:{dt} \\ $$

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