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Question Number 63076 by YSN last updated on 28/Jun/19
show that f:A→B is bijection then f(A_1 ^c )=[f(A_1 )]^c
$${show}\:{that}\:{f}:{A}\rightarrow{B}\:{is}\:{bijection}\:{then}\:{f}\left({A}_{\mathrm{1}} ^{{c}} \right)=\left[{f}\left({A}_{\mathrm{1}} \right)\right]^{{c}} \\ $$

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