Show-that-i-sin-1-2-2-2-in-air-if-the-refractive-index-n-sin-2-60-sin-2-45-

Question Number 156270 by Tawa11 last updated on 09/Oct/21

Show that i = \sin^{- 1} {(\frac{\sqrt{2}}{2})}^{2} in air, if the refractive

index n = \frac{\sin^{2} (60)}{\sin^{2} (45)}

Commented by Tawa11 last updated on 10/Oct/21

Sir, I just know that, refractive index, n = \frac{\sin i}{\sin r}

Answered by ajfour last updated on 10/Oct/21

n_{air} \sin i = n_{medium} \sin r

\sin i = \frac{n_{medium}}{n_{air}} \sin r

= nsin r = \frac{\sin^{2} (60)}{\sin^{2} (45)} \sin r

i = \sin^{- 1} {\frac{\sin^{2} (60)}{\sin^{2} (45)} \sin r}

Commented by Tawa11 last updated on 11/Oct/21

Thanks sir . God bless you .

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