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Question Number 118180 by mathocean1 last updated on 15/Oct/20
show that if n is odd , n(n^2 +3) is even.
showthatifnisodd,n(n2+3)iseven.
Answered by floor(10²Eta[1]) last updated on 15/Oct/20
if n is odd⇒n=2k+1, k∈Z  (2k+1)((2k+1)^2 +3)  =(2k+1)(4k^2 +4k+4)  =4(2k+1)(k^2 +k+1)=even because  it′s a multiple of 2
ifnisoddn=2k+1,kZ(2k+1)((2k+1)2+3)=(2k+1)(4k2+4k+4)=4(2k+1)(k2+k+1)=evenbecauseitsamultipleof2
Commented by mathocean1 last updated on 15/Oct/20
thanks
thanks

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