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Question Number 159716 by mathocean1 last updated on 20/Nov/21
Show that ▽r^n =nr^(n−2) r
$${Show}\:{that}\:\bigtriangledown{r}^{{n}} ={nr}^{{n}−\mathrm{2}} {r} \\ $$
Answered by puissant last updated on 20/Nov/21
▽r^n = nr^(n−1) = nr^(n−2) ×r
$$\bigtriangledown{r}^{{n}} \:=\:{nr}^{{n}−\mathrm{1}} \:=\:{nr}^{{n}−\mathrm{2}} ×{r} \\ $$
Commented by mathocean1 last updated on 23/Nov/21
thanks.

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