show-that-range-of-the-ff-projection-obtained-by-algebric-expression-R-ucos-usin-usin-2-2gh-

Question Number 178632 by Best1 last updated on 19/Oct/22

show that range of the ff projection obtained by algebric expression R=(ucosθ)(usinθ)+(√((usinθ)^2 +2gh))

$${show}\:{that}\:{range}\:{of}\:{the}\:{ff}\:{projection} \\ $$$$\:{obtained}\:{by}\:{algebric}\:{expression}\: \\ $$$${R}=\left({ucos}\theta\right)\left({usin}\theta\right)+\sqrt{\left({usin}\theta\right)^{\mathrm{2}} +\mathrm{2}{gh}} \\ $$

Commented by Best1 last updated on 19/Oct/22

$${please}\:{help}\:{me} \\ $$

Commented by mr W last updated on 19/Oct/22

$${what}\:{you}\:{gave}\:{is}\:{wrong}.\:{Ar}\:{Brandon} \\ $$$${sir}\:{has}\:{given}\:{you}\:{the}\:{correct}\:{answer} \\ $$$${and}\:{corresponding}\:{working}. \\ $$

Commented by Best1 last updated on 19/Oct/22

$${i}\:{corrected}\:{it}\:{sir}\: \\ $$

Commented by mr W last updated on 19/Oct/22

the horizontal range is R=((u cos θ)/g)(u sin θ+(√(u^2 sin^2 θ+2gh))) with h≥0.

$${the}\:{horizontal}\:{range}\:{is} \\ $$$${R}=\frac{{u}\:\mathrm{cos}\:\theta}{{g}}\left({u}\:\mathrm{sin}\:\theta+\sqrt{{u}^{\mathrm{2}} \:\mathrm{sin}^{\mathrm{2}} \:\theta+\mathrm{2}{gh}}\right) \\ $$$${with}\:{h}\geqslant\mathrm{0}. \\ $$

Commented by Best1 last updated on 19/Oct/22