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Question Number 160411 by nadovic last updated on 29/Nov/21
  Show that  tan 58°tan 32° = 1
$$\:\:\mathrm{Show}\:\mathrm{that}\:\:\mathrm{tan}\:\mathrm{58}°\mathrm{tan}\:\mathrm{32}°\:=\:\mathrm{1} \\ $$
Answered by TheSupreme last updated on 29/Nov/21
tan(α)tan((π/2)−α)=tan(α)cotan(α)=1
$${tan}\left(\alpha\right){tan}\left(\frac{\pi}{\mathrm{2}}−\alpha\right)={tan}\left(\alpha\right){cotan}\left(\alpha\right)=\mathrm{1} \\ $$$$ \\ $$

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