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show-that-the-area-of-the-triangle-whose-vertics-area-0-0-0-x-1-y-1-z-1-x-2-y-2-z-2-is-1-2-y-1-z-2-y-2-z-1-2-




Question Number 49466 by munnabhai455111@gmail.com last updated on 07/Dec/18
show that the area of the triangle whose vertics area (0,0,0) , (x_1 ,y_1 ,z_1 ) , (x_2 ,y_(2,) z_2 ) is 1/2((√(Σ(y_1 z_2 −y_2 z_1 )^2  .))
showthattheareaofthetrianglewhoseverticsarea(0,0,0),(x1,y1,z1),(x2,y2,z2)is1/2(Σ(y1z2y2z1)2.

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