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Question Number 171156 by MathsFan last updated on 08/Jun/22
show that the equation    3x^2 +3y^2 −24x+12y+12=0   is a circle
$$\boldsymbol{\mathrm{show}}\:\boldsymbol{\mathrm{that}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{equation}}\: \\ $$$$\:\mathrm{3}\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\mathrm{3}\boldsymbol{\mathrm{y}}^{\mathrm{2}} −\mathrm{24}\boldsymbol{\mathrm{x}}+\mathrm{12}\boldsymbol{\mathrm{y}}+\mathrm{12}=\mathrm{0} \\ $$$$\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{circle}} \\ $$

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