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Show-that-the-function-defined-within-0-1-by-f-x-1-if-x-Q-0-1-0-otherwise-is-not-Riemann-integrable-within-0-1-




Question Number 102763 by Ar Brandon last updated on 10/Jul/20
Show that the function defined within [0,1]  by f(x)= { ((1 if x∈Q∩[0,1])),((0 otherwise)) :}  is not Riemann integrable  within [0,1]
Showthatthefunctiondefinedwithin[0,1]byf(x)={1ifxQ[0,1]0otherwiseisnotRiemannintegrablewithin[0,1]

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