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Question Number 95643 by Ar Brandon last updated on 26/May/20
Show that the function f(x)=x^3  is derivable at all  points x_0 ∈R and that f′(x_0 )=3x_0 ^2
Showthatthefunctionf(x)=x3isderivableatallpointsx0Randthatf(x0)=3x02
Answered by Rio Michael last updated on 26/May/20
lets choose a general point c ∈ R ,  if f(x) = x^3  is derivable or differentiable at x = x_0  = c then  lim_(x→c) ((f(x)−f(c))/(x−c)) must exist.  but f(x) = x^3  ⇒ f(c) = c^3    lim_(x→c)  ((x^3 −c^3 )/(x−c)) = lim_(x→c)  (((x−c)(x^2  + 2cx + c^3 ))/((x−c))) = lim_(x→c)  (x^2  + 2cx + c^2 ) = 3c^2
letschooseageneralpointcR,iff(x)=x3isderivableordifferentiableatx=x0=cthenlimxcf(x)f(c)xcmustexist.butf(x)=x3f(c)=c3limxcx3c3xc=limxc(xc)(x2+2cx+c3)(xc)=limxc(x2+2cx+c2)=3c2

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