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Question Number 90772 by MWSuSon last updated on 26/Apr/20

s h o w t h a t t h e r o o t s o f t h e e q u a t i o n

x^{2} - 2 x = {(b - c)}^{2} - 1 a r e r a t i o n a l i f

b a n d c a r e r a t i o n a l n u m b e r s .

Commented by jagoll last updated on 26/Apr/20

x^{2} - 2 x + 1 = {(b - c)}^{2}

{(x - 1)}^{2} - {(b - c)}^{2} = 0

(x - 1 + b - c) (x - 1 + c - b) = 0

x_{1} = c + 1 - b & x_{2} = b + 1 - c

i f b, c r a t i o n a l n u m b e r t h e n

x_{1} \land x_{2} r a t i o n a l n u m b e r

Commented by MWSuSon last updated on 26/Apr/20

t h a n k y o u s i r, i a p p r e c i a t e

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