Show-that-U-n-4n-1-7n-3-is-convergent-sequence-

Question Number 161168 by mathocean1 last updated on 13/Dec/21

S h o w t h a t U_{n} = \frac{4 n - 1}{7 n + 3} i s c o n v e r g e n t

s e q u e n c e .

Commented by MJS_new last updated on 13/Dec/21

\frac{4 n - 1}{7 n + 3} = \frac{4}{7} - \frac{19}{49 n - 21}

Answered by mathocean1 last updated on 14/Dec/21

t h a n k s \dots

Answered by physicstutes last updated on 15/Dec/21

\lim_{n \to \infty} (\frac{4 n - 1}{7 n + 3}) = \frac{4}{7}

∴ {U_{n}} converges to \frac{4}{7}