Show-that-volume-of-a-region-of-space-bounded-by-a-boundary-surface-S-is-V-1-3-S-rcos-dA-being-the-angle-between-the-position-vector-of-a-point-P-on-the-surface-and-the-outer-normal-to

Question Number 23393 by ajfour last updated on 29/Oct/17

S h o w t h a t v o l u m e o f a r e g i o n

o f s p a c e b o u n d e d b y a b o u n d a r y

s u r f a c e S i s V = \frac{1}{3} \underset{S}{\int \int} r \cos θ d A .

θ b e i n g t h e a n g l e b e t w e e n t h e

p o s i t i o n v e c t o r o f a p o i n t P o n

t h e s u r f a c e, a n d t h e o u t e r n o r m a l

t o t h e s u r f a c e a t P .

r i s t h e d i s t a n c e o f p o i n t P f r o m

o r i g i n .

Commented by ajfour last updated on 07/Nov/19

?

Facebook Tweet Pin