simplfy-sinh-log2-

Question Number 175285 by MathsFan last updated on 26/Aug/22

simplfy

\sinh (\log 2)

Answered by MJS_new last updated on 26/Aug/22

\sinh x = \frac{e^{x} - e^{- x}}{2}

\Rightarrow answer is \frac{3}{4}

Commented by MathsFan last updated on 26/Aug/22

can you please expand it furter ?

Commented by MJS_new last updated on 26/Aug/22

e^{\ln x} = x

{there}^{'} s nothing difficult

Answered by MikeH last updated on 26/Aug/22

\sinh (\ln 2) = \frac{e^{\ln 2} - e^{- \ln 2}}{2} = \frac{2 - \frac{1}{2}}{2} = \frac{3}{4}

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