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Question Number 144708 by mathdanisur last updated on 28/Jun/21
Simplify: ((1/((x-2)!)) - (1/((x-1)!)))∙x!
Simplify:(1(x−2)!−1(x−1)!)⋅x!
Answered by MJS_new last updated on 28/Jun/21
((((x−1)x)/(x!))−(x/(x!)))x!=x^2 −2x=x(x−2)
((x−1)xx!−xx!)x!=x2−2x=x(x−2)
Commented by mathdanisur last updated on 28/Jun/21
cool thankyou Sir
coolthankyouSir
Answered by liberty last updated on 28/Jun/21
((1/((x−2)!))−(1/((x−1)(x−2)!))).x(x−1)(x−2)! =(((x−1−1)/((x−1)(x−2)!))).x(x−1)(x−2)! =(((x−2)/((x−1)(x−2)!))).x(x−1)(x−2)! =(x−2).x
(1(x−2)!−1(x−1)(x−2)!).x(x−1)(x−2)!=(x−1−1(x−1)(x−2)!).x(x−1)(x−2)!=(x−2(x−1)(x−2)!).x(x−1)(x−2)!=(x−2).x
Commented by mathdanisur last updated on 28/Jun/21
thankyou Sir cool
thankyouSircool

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