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Question Number 33575 by MURALI last updated on 19/Apr/18
simplify (√((3+2(√(2)))))
simplify(3+22)
Answered by Rasheed.Sindhi last updated on 19/Apr/18
Let (√((3+2(√(2)))))  =a+b(√2)  where a,b ∈Z     ( (√((3+2(√(2))))) )^2 =(a+b(√2) )^2   a^2 +2b^2 +2ab(√2)=3+2(√2)  a^2 +2b^2 =3 ∧  ab=1  ab=1⇒b=1/a  a^2 +2b^2 =3⇒a^2 +(2/a^2 )=3  a^4 −3a^2 +2=0  (a^2 −1)(a^2 −2)=0  a=±1 , a=±(√2) ∉Z  Hence a=±1                     b=1/(±1)=±1  ∴   (√((3+2(√(2)))))=1+(√2)  ,  −1−(√2)
Let(3+22)=a+b2wherea,bZ((3+22))2=(a+b2)2a2+2b2+2ab2=3+22a2+2b2=3ab=1ab=1b=1/aa2+2b2=3a2+2a2=3a43a2+2=0(a21)(a22)=0a=±1,a=±2ZHencea=±1b=1/(±1)=±1(3+22)=1+2,12
Answered by MURALI last updated on 19/Apr/18
(3+2(√2)  )^2  =((√2) )^2
(3+22)2=(2)2
Commented by Rasheed.Sindhi last updated on 21/Apr/18
Perhaps you mean  (3+2(√2)  )^2  =(1+(√2) )^2
Perhapsyoumean(3+22)2=(1+2)2
Answered by MURALI last updated on 19/Apr/18
(3+ 2(√2) )=((√2) )^2 +2(√2)  ×1+(1)^2   (3+ 2(√2) )=((√2) +1)^2   ∴  (√(3+2(√(2)))))  =  (√2) +1
(3+22)=(2)2+22×1+(1)2(3+22)=(2+1)23+22)=2+1

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