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simplify-interval-number-1-6-3-7-




Question Number 36011 by solihin last updated on 27/May/18
simplify:  ′interval number′  (1,6)∪(3,7)
simplify:intervalnumber(1,6)(3,7)
Commented by Rasheed.Sindhi last updated on 27/May/18
For overlapping intervals (a,b) & (c,d)  (a,b)∪(c,d)=(   min(a,c) , max(b,d)   )
Foroverlappingintervals(a,b)&(c,d)(a,b)(c,d)=(min(a,c),max(b,d))
Commented by Rasheed.Sindhi last updated on 27/May/18
(1,6)∪(3,7)=(1,7)
(1,6)(3,7)=(1,7)

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