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Simplify-x-y-z-x-1-y-1-z-1-x-1-y-1-z-1-x-y-y-z-z-x-




Question Number 43707 by Tawa1 last updated on 14/Sep/18
Simplify:     (x + y + z)(x^(−1)  + y^(−1)  + z^(−1) ) = (x^(−1)  y^(−1)  z^(−1) )(x + y)(y + z)(z + x)
Simplify:(x+y+z)(x1+y1+z1)=(x1y1z1)(x+y)(y+z)(z+x)
Commented by math1967 last updated on 14/Sep/18
Simplify ???/prove??
Simplify???/prove??
Commented by Tawa1 last updated on 14/Sep/18
It should be prove sir
Itshouldbeprovesir
Commented by Tawa1 last updated on 14/Sep/18
thanks
thanks
Answered by math1967 last updated on 14/Sep/18
I think L.H.S  =(x+y+z)(x^(−1) +y^(−1) +z^(−1) )−1  =(x+y+z)(((yz+zx+xy)/(xyz)))−1  =(((x+y+z)(xy+yz+zx)−xyz)/(xyz))  =((z(x+y)^2 +xy(x+y)+z^2 (x+y)+xyz−xyz)/(xyz))  =(((x+y)(zx+zy+xy+z^2 ))/(xyz))  =(((x+y)(y+z)(z+x))/(xyz))  =((1/(xyz)))(x+y)(y+z)(z+x)  =(x^(−1) y^(−1) z^(−1) )(x+y)(y+z)(z+x)  =R.H.S
IthinkL.H.S=(x+y+z)(x1+y1+z1)1=(x+y+z)(yz+zx+xyxyz)1=(x+y+z)(xy+yz+zx)xyzxyz=z(x+y)2+xy(x+y)+z2(x+y)+xyzxyzxyz=(x+y)(zx+zy+xy+z2)xyz=(x+y)(y+z)(z+x)xyz=(1xyz)(x+y)(y+z)(z+x)=(x1y1z1)(x+y)(y+z)(z+x)=R.H.S
Commented by Tawa1 last updated on 14/Sep/18
God bless you sir
Godblessyousir

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