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sin-1-1-5-cot-1-3-




Question Number 64773 by ankan0 last updated on 21/Jul/19
sin^(−1) (1/(√(5)))+cot^(−1) 3
sin1(1/5)+cot13
Answered by Kunal12588 last updated on 21/Jul/19
cot^(−1) (a)=sin^(−1) ((1/( (√(1+a^2 )))))  cot^(−1) 3=sin^(−1) ((1/( (√(1+9)))))=sin^(−1) (1/( (√(10))))  sin^(−1) a+sin^(−1) b=sin^(−1) (a(√(1−b^2 ))+b(√(1−a^2 )))  sin^(−1) (1/(√5))+cot^(−1) 3  =sin^(−1) (1/( (√5)))+sin^(−1) (1/( (√(10))))  =sin^(−1) ((1/( (√5)))(√(1−(1/(10))))+(1/( (√(10))))(√(1−(1/5))))  =sin^(−1) ((3/( (√5)(√(10))))+(2/( (√(10))(√5))))  =sin^(−1) ((5/(5(√2))))  =sin^(−1) ((1/( (√2))))  =(π/4)=45°
cot1(a)=sin1(11+a2)cot13=sin1(11+9)=sin1110sin1a+sin1b=sin1(a1b2+b1a2)sin1(1/5)+cot13=sin115+sin1110=sin1(151110+110115)=sin1(3510+2105)=sin1(552)=sin1(12)=π4=45°
Commented by John M. Kaloki last updated on 13/Aug/19
I can
Ican

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