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sin-1-sin-2-csc-2-tan-2-




Question Number 163926 by cortano1 last updated on 12/Jan/22
              {: ((sin θ=1−sin^2 θ)),((csc^2 θ−tan^2 θ =? )) }
$$\:\:\:\:\:\:\:\:\:\:\:\:\:\left.\begin{matrix}{\mathrm{sin}\:\theta=\mathrm{1}−\mathrm{sin}\:^{\mathrm{2}} \theta}\\{\mathrm{csc}\:^{\mathrm{2}} \theta−\mathrm{tan}\:^{\mathrm{2}} \theta\:=?\:}\end{matrix}\right\} \\ $$
Answered by MJS_new last updated on 12/Jan/22
s^2 =1−s  ⇒  (1/s^2 )−(s^2 /(1−s^2 ))=(1/(1−s))−((1−s)/s)=((s−(1−s)^2 )/(s−s^2 ))=((4s−2)/(2s−1))=2
$${s}^{\mathrm{2}} =\mathrm{1}−{s} \\ $$$$\Rightarrow \\ $$$$\frac{\mathrm{1}}{{s}^{\mathrm{2}} }−\frac{{s}^{\mathrm{2}} }{\mathrm{1}−{s}^{\mathrm{2}} }=\frac{\mathrm{1}}{\mathrm{1}−{s}}−\frac{\mathrm{1}−{s}}{{s}}=\frac{{s}−\left(\mathrm{1}−{s}\right)^{\mathrm{2}} }{{s}−{s}^{\mathrm{2}} }=\frac{\mathrm{4}{s}−\mathrm{2}}{\mathrm{2}{s}−\mathrm{1}}=\mathrm{2} \\ $$
Answered by cortano1 last updated on 12/Jan/22

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