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sin-1-x-a-x-dx-




Question Number 151587 by peter frank last updated on 22/Aug/21
∫sin^(−1) (√(x/(a+x))) dx
sin1xa+xdx
Answered by MJS_new last updated on 22/Aug/21
u′=1 → u=x  v=arcsin (√(x/(x+a))) → v′=((√a)/(2(x+a)(√x)))  ∫arcsin (√(x/(x+a))) dx=  =xarcsin (√(x/(x+a))) −((√a)/2)∫((√x)/(x+a))dx=  =xarcsin (√(x/(x+a))) −(√(ax))+aarcsin (√(x/(x+a))) =  =−(√(ax))+(x+a)arcsin (√(x/(x+a))) +C
u=1u=xv=arcsinxx+av=a2(x+a)xarcsinxx+adx==xarcsinxx+aa2xx+adx==xarcsinxx+aax+aarcsinxx+a==ax+(x+a)arcsinxx+a+C

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