sin-101x-sinx-99-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 82617 by necxxx last updated on 23/Feb/20 ∫sin(101x)(sinx)99dx Answered by TANMAY PANACEA last updated on 23/Feb/20 ∫sin(n+1)xsinn−1xdxn=100∫(sinnxcosx+cosnxsinx)sinn−1xdx∫(sinnxcosxsinn−1x+cosnxsinnx)dx∫(sinnx×d(sinnx)dx×1n+sinnx×d(sinnx)dx×1n)dx1n∫ddx(sinnx.sinnx)dx1n(sinnx.sinnx)+c1100(sin100xsin100x)+c Commented by peter frank last updated on 23/Feb/20 helpqn74411 Commented by TANMAY PANACEA last updated on 23/Feb/20 okletmesee Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: sin-4-2-cos-4-2-1-2-Next Next post: Find-the-normalization-constant-Ne-i-sin- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.