sin-16-cos-16-without-using-cos-3-algebric-method-please- Tinku Tara June 4, 2023 Trigonometry 0 Comments FacebookTweetPin Question Number 58521 by malwaan last updated on 24/Apr/19 \boldsymbolsin16°=?\boldsymbolcos16°=?\boldsymbolwithout\boldsymbolusing\boldsymbolcos(3θ)\boldsymbolalgebric\boldsymbolmethod\boldsymbolplease Answered by tanmay last updated on 24/Apr/19 tryingcalculusmethody=sinxdydx=cosxdydx≈△y△x△y=dydx△xnowx=15ox+△x=16oso△x=1o=π180radiansin15o=sin(45−30)=sin45ocos30o−cos45osin30osin15o=12×32−12×12=3−122cos15o=cos(45o−30o)=12×32+12×12cos15o=3+122△y=dydx×△x△y=(cosx)△x△y=cos15o×π180△y=(3+122)×π180hencesin16o=3−122+3+122×π180sin16o=0.2726776311sin16o≈0.2726nowify=cosxdydx=△y△x=−sinx△y=(−sinx)△x=(−3−122)×π180=(−0.0045172445)socos(16o)=3+122−0.0045172445cos16o=0.9614085818≈0.9614 Commented by malwaan last updated on 25/Apr/19 thankyousomuchsirthankyousomuchsir Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-58519Next Next post: find-0-x-3-sin-2x-x-2-x-1-3-dx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.