sin-2-x-cos-2-x- Tinku Tara June 4, 2023 Trigonometry 0 Comments FacebookTweetPin Question Number 190993 by mathlove last updated on 16/Apr/23 sin2x⋅cos2x=? Answered by cortano12 last updated on 16/Apr/23 =14sin22x Answered by mustafazaheen last updated on 16/Apr/23 =[22sin(x)⋅cos(x)][22sin(x)⋅cos(x)]=sin(2x)2×sin(2x)2=14sin2(2x) Answered by manxsol last updated on 16/Apr/23 y=sin2x⋅cos2x4y=4sin2x⋅cos2x4y=(2sinxcosx)24y=(sin2x)2y=(sin2x)24 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-125456Next Next post: Question-190998 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.