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sin-pi-24-cos-pi-24-cos-pi-12-




Question Number 145852 by mathdanisur last updated on 08/Jul/21
sin(π/(24))∙cos(π/(24))∙cos(π/(12))=?
sinπ24cosπ24cosπ12=?
Answered by waiphyoemaung last updated on 08/Jul/21
solution  sin(π/(24)).cos(π/(24)).cos(π/(12))  =(1/2).(2sin(π/(24))cos(π/(24)))cos(π/(12))  =(1/2).sin(π/(12)).cos(π/(12))  (∵sin 2α=2sin α cos α)  =(1/4).2sin(π/(12)).cos(π/(12))  =(1/4).sin(π/6)  =(1/4)×(1/2)   (∵sin(π/6)=(1/2))  =(1/8)
solutionsinπ24.cosπ24.cosπ12=12.(2sinπ24cosπ24)cosπ12=12.sinπ12.cosπ12(sin2α=2sinαcosα)=14.2sinπ12.cosπ12=14.sinπ6=14×12(sinπ6=12)=18
Commented by mathdanisur last updated on 08/Jul/21
Thanks Ser cool
ThanksSercool

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