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Question Number 89202 by jagoll last updated on 16/Apr/20
sin ((π/7))sin (((2π)/7))sin (((3π)/7)) =?
sin(π7)sin(2π7)sin(3π7)=?
Commented by jagoll last updated on 16/Apr/20
where sir?
wheresir?
Commented by jdmath last updated on 16/Apr/20
Dr. peyam video may be helpful
Dr.peyamvideomaybehelpful
Commented by jdmath last updated on 16/Apr/20
youtube...i wasnt able to copy the link..search it
youtubeiwasntabletocopythelink..searchit
Commented by john santu last updated on 16/Apr/20
Π_(k=2) ^n  sin ((((k−1)π)/n)) = (n/2^(n−1) )  n = 7   sin ((π/7))sin (((2π)/7))sin (((3π)/7))sin (((4π)/7))  sin (((5π)/7))sin (((6π)/7)) = (7/(64))  ...(i)  sin ((π/7))=sin (((6π)/7))  sin (((2π)/7))=sin (((5π)/7))  sin (((3π)/7))=sin (((4π)/7))  (sin (π/7)sin ((2π)/7)sin ((3π)/7))^2  = (7/(64))  ⇒ sin (π/7)sin ((2π)/7)sin ((3π)/7) = (√(7/(64)))  = ((√7)/8)
nk=2sin((k1)πn)=n2n1n=7sin(π7)sin(2π7)sin(3π7)sin(4π7)sin(5π7)sin(6π7)=764(i)sin(π7)=sin(6π7)sin(2π7)=sin(5π7)sin(3π7)=sin(4π7)(sinπ7sin2π7sin3π7)2=764sinπ7sin2π7sin3π7=764=78

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