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Question Number 164511 by HongKing last updated on 18/Jan/22
sin∙(π sin x) - cos∙(π sin x) = 1  find  x=?
sin(πsinx)cos(πsinx)=1findx=?
Answered by mindispower last updated on 18/Jan/22
sin(a)−cos(a)=(√2)sin(a−(π/4))  ⇔ withea=πsin(x)  sin(a−(π/4))=(1/( (√2)))  ⇔a−(π/4)=(π/4)+2kπ,((3π)/4)+2kπ  sin(x)=1+2k∈{1,−1}  x=(π/2)+kπ  πsin(x)=(π/2)+2kπ  sin(x)=(1/2)+2k,  ⇒k=0  sin(x)=(1/2),x∈{(π/6)+2kπ,((5π)/6)+2kπ}
sin(a)cos(a)=2sin(aπ4)withea=πsin(x)sin(aπ4)=12aπ4=π4+2kπ,3π4+2kπsin(x)=1+2k{1,1}x=π2+kππsin(x)=π2+2kπsin(x)=12+2k,k=0sin(x)=12,x{π6+2kπ,5π6+2kπ}
Commented by HongKing last updated on 20/Jan/22
thank you dear Sir cool
thankyoudearSircool

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