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sin-sin-3-sin5-cos-cos-3-cos-5-tan-3-




Question Number 20703 by tammi last updated on 01/Sep/17
((sinα+sin 3α+sin5α)/(cos α+cos 3α+cos 5α))=tan 3α
sinα+sin3α+sin5αcosα+cos3α+cos5α=tan3α
Commented by myintkhaing last updated on 01/Sep/17
L.H.S=((2sin3αcos2α+sin3α)/(2cos3αcos2α+cos3α))=((sin3α)/(cos3α))=tan3α  proved
L.H.S=2sin3αcos2α+sin3α2cos3αcos2α+cos3α=sin3αcos3α=tan3αproved
Answered by myintkhaing last updated on 01/Sep/17

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