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sin-x-1-x-0-05-0-1-




Question Number 56647 by ANTARES VY last updated on 20/Mar/19
sin((𝛑/x))=1  x∈[0.05;0.1]
sin(πx)=1x[0.05;0.1]
Commented by ajfour last updated on 20/Mar/19
sin ((π/x))=sin ((π/2)+2kπ)  k∈{5,6,7,8,9}  ⇒  x=(2/(4k+1)) = {(2/(21)),(2/(25)),(2/(29)),(2/(33)),(2/(37))}
sin(πx)=sin(π2+2kπ)k{5,6,7,8,9}x=24k+1={221,225,229,233,237}

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