Question Number 47807 by gunawan last updated on 15/Nov/18
$$\mathrm{sin}\:{xy}^{\mathrm{2}} ={y}^{\mathrm{2}} +\mathrm{2}{x} \\ $$$$ \\ $$$$\mathrm{diferential}\:{express}\:\mathrm{is} \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 15/Nov/18
$${cos}\left({xy}^{\mathrm{2}} \right)\left\{{x}×\mathrm{2}{ydy}+{y}^{\mathrm{2}} {dx}\right\}=\mathrm{2}{ydy}+\mathrm{2}{dx} \\ $$