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sin18-0-




Question Number 21815 by gopikrishnan005@gmail.com last updated on 04/Oct/17
sin18^0 =
$${sin}\mathrm{18}^{\mathrm{0}} = \\ $$
Commented by Tinkutara last updated on 04/Oct/17
(((√5)−1)/4)
$$\frac{\sqrt{\mathrm{5}}−\mathrm{1}}{\mathrm{4}} \\ $$
Commented by math solver last updated on 05/Oct/17
emmm .    use identity  sin 3A=3sin A−4sin^3 A
$${emmm}\:.\:\: \\ $$$${use}\:{identity}\:\:\mathrm{sin}\:\mathrm{3}{A}=\mathrm{3sin}\:{A}−\mathrm{4sin}\:^{\mathrm{3}} {A} \\ $$

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