Question Number 182854 by manxsol last updated on 16/Dec/22

Commented by manxsol last updated on 16/Dec/22

Commented by Frix last updated on 15/Dec/22

Commented by manxsol last updated on 15/Dec/22

Commented by manxsol last updated on 15/Dec/22

Commented by Frix last updated on 15/Dec/22

Commented by manxsol last updated on 15/Dec/22
![I solved it like this sin54=(((√5)+1)/4)=(1/2) (((√5)+1)/2)=(1/2)Φ ((1/2))^(10) Φ^(10) =(1/(1024)) (((123+55(√5))/2)) =((123+55(√5))/(2048))=x_1 See (★)^ roots integer⇒x_(2 conjugate) x_2 =((123−55(√5))/(2048)) x_1 +x_2 =((246)/(2048)) x_1 x_2 =(4/(4194304)) calculate using editor tinku tara 2048^2 4194304.0 123^2 −5×55^2 4.0 246×2048 503808.0 4194304/4 1048576.0 503808/4 125952.0 input 4×5 [push] enter [push] ⋮ [push] calcular 20.0 x^2 −((246)/(2048))x+(4/(4194304))=0 4194304x^2 −503808x+4=0 1048576x^2 −125952x+1=0 solution: a=1048576 (★) Φ^(10) =(((1+(√5))/2))^(10) =((123+55(√5))/2) serie de fibonacci determinant ((1,2,3,4,5,6,7,8,9,(10),(11)),(1,1,2,3,5,8,(13),(21),(34),(55),(89))) a=55 b=123 deduccion hecha de tabla de potencias de Φ=(1+(√5))/2](https://www.tinkutara.com/question/Q182871.png)
Commented by Frix last updated on 15/Dec/22
