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sinx-3-dx-




Question Number 124906 by Mammadli last updated on 06/Dec/20
∫sinx^3 dx=?
sinx3dx=?
Commented by Dwaipayan Shikari last updated on 06/Dec/20
∫sinx^3 dx            =(1/(2i))∫e^(ix^3 ) −e^(−ix^3 ) dx   =((ix(√(ix^3 )))/(6x^2 ))Γ((1/3),ix^3 )+((ix(√(−ix^3 )))/(6x^2 ))Γ((1/3),−ix^3 ) (Incomplete gamma)
sinx3dx=12ieix3eix3dx=ixix36x2Γ(13,ix3)+ixix36x2Γ(13,ix3)(Incompletegamma)

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