sinx-cosx-cos2x-cos4x-dx-

Question Number 102099 by Study last updated on 06/Jul/20

\int s i n x \cdot c o s x \cdot c o s 2 x \cdot c o s 4 x d x = ?

Answered by PRITHWISH SEN 2 last updated on 06/Jul/20

\frac{1}{2} \int \sin 2 xcos 2 xcos 4 x dx = \frac{1}{4} \int \sin 4 xcos 4 xdx

= \frac{1}{8} \int \sin 8 xdx = - \frac{\cos 8 x}{64} + C

yes you are right .

Commented by Study last updated on 06/Jul/20

\frac{1}{8} \int s i n 8 x d x = - \frac{1}{64} c o s 8 x + C r i g h t ?

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