sinx-cosx-cos2x-cos4x-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 102099 by Study last updated on 06/Jul/20 ∫sinx⋅cosx⋅cos2x⋅cos4xdx=? Answered by PRITHWISH SEN 2 last updated on 06/Jul/20 12∫sin2xcos2xcos4xdx=14∫sin4xcos4xdx=18∫sin8xdx=−cos8x64+Cyesyouareright. Commented by Study last updated on 06/Jul/20 18∫sin8xdx=−164cos8x+Cright? Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-102096Next Next post: Question-167633 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.