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sketch-x-2-y-3-and-x-2-y-2-16-and-hence-solve-x-2-y-3-x-2-y-2-16-0-

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Question Number 100767 by Rio Michael last updated on 28/Jun/20
sketch x^2 = y^3 and x^2 + y^2 = 16 and hence solve (x^2 −y^3 )(x^2 + y^2 −16) ≥0
sketchx2=y3andx2+y2=16andhencesolve(x2−y3)(x2+y2−16)⩾0
Answered by john santu last updated on 28/Jun/20
Answered by john santu last updated on 28/Jun/20

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