smlify-X-p-2-n-p-3-1-p-3-1-by-using-1-j-j-2-and-j-e-i2pi-3-

Tinku Tara June 4, 2023 Algebra 0 Comments

Question Number 26998 by abdo imad last updated on 01/Jan/18

smlify X= Π_(p=2) ^n ((p^3 −1)/(p^3 +1)) by using 1,j,j^2 and j=e^((i2π)/3) .

$${smlify}\:{X}=\:\:\prod_{{p}=\mathrm{2}} ^{{n}} \frac{{p}^{\mathrm{3}} −\mathrm{1}}{{p}^{\mathrm{3}} \:+\mathrm{1}}\:{by}\:{using}\:\mathrm{1},{j},{j}^{\mathrm{2}} {and}\:{j}={e}^{\frac{{i}\mathrm{2}\pi}{\mathrm{3}}} . \\ $$

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smlify-X-p-2-n-p-3-1-p-3-1-by-using-1-j-j-2-and-j-e-i2pi-3-

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