Question Number 125666 by fajri last updated on 12/Dec/20
$${solution}\:: \\ $$$$ \\ $$$${x}'\:=\:\begin{pmatrix}{−\mathrm{2}\:\:\:\:\:\:\:\:\mathrm{1}}\\{\mathrm{1}\:\:\:\:\:\:\:\:−\mathrm{2}}\end{pmatrix}{x}\:+\:\begin{pmatrix}{\mathrm{2}{e}^{−{m}} }\\{\mathrm{3}{m}}\end{pmatrix} \\ $$