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solve-1-1-x-2-d-lnx-




Question Number 23663 by Anoop kumar last updated on 03/Nov/17
solve    ∫^1_  _(−1) x^2 d(lnx)
solve11x2d(lnx)
Commented by prakash jain last updated on 03/Nov/17
You are correct. Thanks.
Youarecorrect.Thanks.
Commented by prakash jain last updated on 03/Nov/17
Does the integral converge?  ln x for x=−1?
Doestheintegralconverge?lnxforx=1?
Commented by $@ty@m last updated on 03/Nov/17
Here lnx=−1  not x
Herelnx=1notx
Answered by $@ty@m last updated on 03/Nov/17
Let ln x=t  ⇒e^t =x  ∫^1_  _(−1) x^2 d(lnx)=∫_(−1) ^1 e^(2t) dt  =[(e^(2t) /2)]_(−1) ^1   =((e^2 −e^(−2) )/2)
Letlnx=tet=x11x2d(lnx)=11e2tdtMissing \left or extra \right=e2e22

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