solve-1-iz-1-iz-n-1-itan-1-itan-with-pi-2-lt-lt-pi-2-

Question Number 34673 by math khazana by abdo last updated on 09/May/18

s o l v e {(\frac{1 + i z}{1 - i z})}^{n} = \frac{1 + i t a n α}{1 - i t a n α} w i t h - \frac{π}{2} < α < \frac{π}{2}