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solve-1-x-x-2-2-x-x-2-




Question Number 180785 by Vynho last updated on 17/Nov/22
solve (1−x−x^2 ...)(2−x−x^2 ...)
solve(1xx2)(2xx2)
Answered by Rasheed.Sindhi last updated on 17/Nov/22
( 1−(x+x^2 +...) )( 2−(x+x^2 +...) )  If ∣x∣<1:  (1−(x/(1−x)))(2−(x/(1−x)))  ((1−x−x)/(1−x))∙((2−2x−x)/(1−x))  =(((1−2x)(2−3x))/((1−x)^2 ))=((6x^2 −7x+2)/(x^2 −2x+1))
(1(x+x2+))(2(x+x2+))Ifx∣<1:(1x1x)(2x1x)1xx1x22xx1x=(12x)(23x)(1x)2=6x27x+2x22x+1
Answered by mr W last updated on 17/Nov/22
let t=x+x^2 +...=x(1+x+x^2 +...)  ⇒(1−t)(2−t)=0  ⇒t=1 or 2  ⇒x(1+x+x^2 +...)=1 or 2   x<1  (x/(1−x))=1 or 2  ⇒x=(1/2) or (2/3)
lett=x+x2+=x(1+x+x2+)(1t)(2t)=0t=1or2x(1+x+x2+)=1or2x<1x1x=1or2x=12or23

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